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feat(OEIS): add solutions from AlphaProof Nexus#4384

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feat(OEIS): add solutions from AlphaProof Nexus#4384
mo271 wants to merge 20 commits into
google-deepmind:mainfrom
mo271:solved_oeis

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@mo271

@mo271 mo271 commented Jul 3, 2026

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This upstreams the findings of https://github.com/google-deepmind/alphaproof-nexus-results/tree/main/APNOutputs/OEIS
from https://arxiv.org/abs/2605.22763.

As a follow up we plan to also potenially add the (cleaned-up) unsolved questions that remain, see here:
https://github.com/google-deepmind/formal-conjectures/tree/auto_oeis/FormalConjectures/OEIS/Auto

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github-actions Bot commented Jul 3, 2026

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👋 This is an automated welcome message. 🤖
Thanks for the contributions!

A few friendly reminders while the review gets started:

  • Please take a look at the style guidelines,
    especially the conventions for references, categories, AMS tags, and answer(sorry).
  • You can manage some PR labels by leaving a comment with +label-name or -label-name; for example, +awaiting-author or -awaiting-author.
  • This repository is mainly for formalised statements. Proofs longer than about 25-50 lines are usually out of scope; longer proofs are welcome to be included/linked via the formal_proof mechanism.

Thanks again for helping improve Formal Conjectures.

@github-actions github-actions Bot added the oeis Conjectures from oeis.org label Jul 3, 2026
The sequence $a(n)$ satisfies the linear recurrence relation:
$$a(n) = 3a(n-1) - 4a(n-2) + 2a(n-3) - a(n-4)$$
with initial terms $a(0)=0, a(1)=1, a(2)=1, a(3)=0$.
The sequence takes values in $\mathbb{Z}$.

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There is no verbatim citation of the conjecture: all elements in absolute value are Fibonacci numbers. It seems like the conjecture is that all values are integers.


A000108 Catalan numbers: C(n) = binomial(2n,n)/(n+1).

The sum $\sum_{i=j}^k \frac{1}{a(i)}$ of reciprocals of Catalan numbers.

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This isn't the full statement of the conjecture.
Conjecture: All the rational numbers Sum_{i=j..k} 1/a(i) with 0 < min{2,k} <= j <= k have pairwise distinct fractional parts.


@[category test, AMS 11]
lemma a_one : a 1 = 1 := by rfl

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a 2 is missing.

The sequence $a(n)$ is defined by the initial conditions $a(0)=-1, a(1)=4, a(2)=176, a(3)=3136$,
and the linear recurrence relation
$a(n) = -4 * a (n-1) + 256 * a (n-3) + 4096 * a (n-4)$ for $n \ge 4$.

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The statement of the conjecture is missing.

-/
@[category research solved, AMS 11, formal_proof using formal_conjectures at
"https://github.com/mo271/formal-conjectures/blob/a32396489dcb8f86c3549b93aa358ac6a10a3a1f/FormalConjectures/OEIS/113254.wip.lean#L130"]
theorem a_odd_is_square : ∀ n : ℕ, IsSquare (a (2 * n + 1)) := by

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The statement is for a(m, n), a more general sequence. It seems to me the proof is just for m=8, it doesn't prove the full conjecture.

A227582: Expansion of $(2+3*x+2*x^2+2*x^3+3*x^4+x^5-x^6)/(1-2x+x^2-x^5+2*x^6-x^7)$.
The sequence is 1-indexed in OEIS, so $a(n)$ is the $(n-1)$-th term of the 0-indexed solution.

A formal proof has been found with the methods described in [arxiv/2605.22763](https://arxiv.org/abs/2605.22763).

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The conjecture statement is missing.



/--
The sequence $b_n$ such that $A227582(n) = b_{n-1}$ for $n \ge 1$.

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As before this comment is duplicated with the one above.


@[category test, AMS 11]
lemma a_four : a 4 = 674708032182398976 := by sorry

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a 5 is missing.



/--
A237271: Number of parts in the symmetric representation of $\sigma(n)$.

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Same observations as before about the comment.

d_{k+1} \text{ is odd and } d_{k+1} \ge 2 d_k\}|$,
which is a known characterization of the sequence.

A formal proof has been found with the methods described in [arxiv/2605.22763](https://arxiv.org/abs/2605.22763).

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There are multiple conjectures in the webpage, should all be included here?

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