ErdosProblems: add 443, 484, 487, 497, 498, 502, 537, 582, 618, 646 (#3998 sync)#4371
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ErdosProblems: add 443, 484, 487, 497, 498, 502, 537, 582, 618, 646 (#3998 sync)#4371williamjblair wants to merge 1 commit into
williamjblair wants to merge 1 commit into
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Adds Formal Conjectures statements for Erdős problems 443, 484, 487, 497, 498, 502, 537, 582, 618, 646.
Each statement follows the boxed problem text on erdosproblems.com (docstrings verbatim), cross-checked against the two hosted Lean proofs (plby and jayyhk).
formal_prooflinks are pinned to a commit and included only where the hosted proof passed an axiom and hypothesis audit as unconditional.Where a drafted statement departs from the hosted formalizations, the load-bearing choices:
{k(m-k) : 1 ≤ k ≤ m/2}per the text; the hosted proofs use1 ≤ r ≤ k-1, and the two images are equal by the symmetryk ↦ m-k. Carriesn < mas in both hosted theorems, since atm = nthe intersection is all ofA nand the(mn)^{o(1)}bound is not intended.c * N ≤ cardover ℝ, verbatim from the text; the hosted proofs use the natural floor⌊c·N⌋₊. Equivalent up to rescaling the existentialc.Set.HasPosDensity(the FC convention, cf. 741); both hosted proofs assume onlylowerDensity A > 0, a weaker hypothesis, so the pinned proof covers this statement.= 2^{(1+o(1))·C(n, n/2)}; plby proves the equivalent log-side asymptotic. Counts viaNat.cardof a subtype instead of a classicalfilter.1 ≤ ‖z_i‖with the open unit disc. The closed-disc reading is false under that hypothesis (n = 1,z = 1: the closed disc at 0 contains both ±1), and Kleitman's proof is of the open-disc form.C(n+1, 2)andC(n+2, 2); what is solved (and machine-verified) is the Bannai–Bannai–Stanton upper bound, so the statement is|A| ≤ C(n+2, 2)rather than anIsGreatestform.answer(False) ↔ Pwith the text's ground set{1,…,N}(Finset.Icc 1 N, agreeing with jayyhk); plby usesFinset.range (N+1), which admits0 ∈ Aand trivializes the inner pattern. Both refutations go through the same Ruzsa counterexample.G.CliqueFree 4per the text ("contains no K₄", agreeing with jayyhk); plby proves the strictly strongercliqueNum = 3, which implies this statement.h(G)is read as theh₂(G)the problem itself defines.e = 0.Happy to expand on any of these in review, including the hosted-vs-hosted disagreements.
Part of #3998.